# 5.2 The Bernoulli-Euler Beam Theory

The *Bernoulli-Euler* (Euler pronounced 'oiler') beam theory is effectively a model for how beams behave under axial forces and bending. It was developed around 1750 and is still the method that we most often use to analyse the behaviour of bending elements. This model is the basis for all of the analyses that will be covered in this book.

The Bernoulli-Euler beam theory relies on a couple major assumptions. Of course, there are other more complex models that exist (such as the *Timoshenko* beam theory); however, the Bernoulli-Euler assumptions typically provide answers that are 'good enough' for design in most cases.

## Bernoulli-Euler Assumptions

The two primary assumptions made by the Bernoulli-Euler beam theory are that 'plane sections remain plane' and that deformed beam angles (slopes) are small.

The plane sections remain plane assumption is illustrated in Figure 5.1. It assumes that any section of a beam (i.e. a cut through the beam at some point along its length) that was a flat plane before the beam deforms will remain a flat plane after the beam deforms (i.e. it will not curve out-of-plane as shown in the lower right image within Figure 5.1). This assumption is generally relatively valid for bending beams unless the beam experiences significant shear or torsional stresses relative to the bending (axial) stresses. Shear stresses in beams may become large relative to the bending stresses in cases where a beam is very deep and short in length.

The plane sections remain plane assumption also assumes that any section of a beam that was perpendicular to the neutral axis before the beam deforms will remain perpendicular to the neutral axis after the beam deforms. Recall that, depending on the cross-sectional shape of the beam and its composition, the neutral axis may not be located at the centre of the beam height.

If we assume that the deformed angles (slopes) of the beam are small ($\theta$ in Figure 5.1), then there are a few benefits from a calculation standpoint. If $x$ is the location along the length of the beam, and $\Delta(x)$ is the displacement of the beam at location $x$, then the slope ($\theta$) of the beam is:

\begin{equation}

\theta = \frac{d\Delta}{dx}

\end{equation}

or the change in $\Delta$ with respect to $x$ (you can also think of this as rise over run). If the slope $\theta$ is small, then it stands to reason that the square of the slope would be doubly small and can assumed to be equal to zero:

\begin{equation}

\theta^2=\left( \frac{d\Delta}{dx} \right) ^2 \approx 0

\end{equation}

In addition, for small angles, the following approximations are also valid (as shown in Table 5.1):

\begin{align}

\sin \theta \approx \theta \\

\cos \theta \approx 1

\end{align}

if $\theta$ is in radians. As the table shows, up to $\ang{5}$, these approximations are almost exact to three significant figures. At $\ang{10}$, there may be up to $1.5\%$ of error.

## The Bernoulli-Euler Beam Equation

Based on the assumptions discussed above, the Bernoulli-Euler Beam Theory results in the following equation:

\begin{equation}

\boxed{ \frac{d^2\Delta}{dx^2} = \frac{M}{EI} }

\end{equation}

where $ \frac{d^2\Delta}{dx^2}$ is the second derivative of the deflection of the beam $\Delta$ with respect to the position along the beam $x$, $M$ is the internal moment in the beam at location $x$, $E$ is the Young's modulus of the beam material, and $I$ is the moment of inertia (second moment of area) of the beam cross-section. This differential equation applies for any point along the beam, as long as our assumptions (plane sections remain plane and small angles) remain reasonably valid. The derivation of this equation may be found elsewhere in other structural analysis texts.

For the purposes of this course, the following points about the Bernoulli-Euler beam equation are important to know and understand:

-- Curvature (symbol $\phi$) is a measure of how much a beam is deforming at a point in bending (the intensity of the curve). One consequence of the plane sections remain plane assumption is that the strain profile is linear as shown in Figure 5.2. The slope of that linear strain profile is equal to the curvature of the beam at that point. For the situation shown in Figure 5.2, the slope of the strain profile (curvature) may be calculated as:*Curvature*is equal to the slope of the strain profile

\begin{equation*}

\phi = \frac{y}{\epsilon}

\end{equation*}where $y$ is the distance to the top fibre from the neutral axis, and $\epsilon$ is the strain at that top fibre.

*The*-- If the curve at a point on the beam was matched up with a circle of the same curvature, then the radius of curvature (symbol $R$) is the radius of that circle. It can be calculated from the curvature by:*Radius of Curvature*is the Inverse of the Curvature

\begin{equation}

\boxed{R = \frac{1}{\phi}}

\end{equation}*Curvature is approximately equal to the second derivative of the deflection with respect to position*:

\begin{equation}

\boxed {\phi = \frac{1}{R} \approx \frac{d^2\Delta}{dx^2}}

\end{equation}which is also equivalent to the change in slope with respect to position:

\begin{equation}

\boxed {\phi = \frac{1}{R} \approx \frac{d\theta}{dx}}

\end{equation}*Curvature is directly related to the moment*:

\begin{equation}

\boxed{\phi = \frac{M}{EI} }

\end{equation}Therefore:

\begin{equation}

\boxed {\frac{d^2\Delta}{dx^2} =\frac{d\theta}{dx} \approx \frac{M}{EI} } \label{eq:mom-curv}

\end{equation}